f(x)＝sin(x＋π/3)－√3cos(2π/3－x)＝sin(x＋π/3)＋√3cos[π－(2π/3－x)] ＝sin(x＋π/3)＋√3cos(x＋π/3)＝2[1/2×sin(x＋π/3)＋√3/2×cos(x＋π/3)] ＝2sin[(x＋π/3)＋π/3]＝2sin[(x＋2π/3)(1...