曲线f(x)=x³-2x²+3求导f'(x)=3x²-4x3x²-4x=4解得x=2或x=-2/3当x=2是f(2)=3此时切线方程为y=4(x-2)+3即y=4x+5所以a=5切点(2,3)当x=-2/3是f(-2/3)=-5/27此时切线方程y=4(x+2/3)-5/27即y=4x+67/27...