[3x/(x-2)+x/(x+2)]/[x/(x²-4)]={[3x(x+2)+x(x-2)]/(x²-4)}/[x/(x²-4)]=[(4x²+4x)/(x²-4)]/[x/(x²-4)]=[4x(x+1)/(x²-4)]/[x/(x²-4)]=4x+4=4×(-3)+4=-8