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数学
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已知tan(π/4+a)=1/2,求sin(2a+2π)-sin²(π/2-a)/1-cos(π-2a)的值?
人气:114 ℃ 时间:2020-05-27 13:34:51
解答
[sin(2a+2π)-sin²(π/2-a)]/[1-cos(π-2a)]=[sin2a-cos^2a]/[1+cos2a]=cosa[2sina-cosa]/2cos^2a=tana-1/2=-1/3-1/2=-5/6tan(π/4+a)=(1+tana)/(1-tana) tana=-1/3
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