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已知函数f(x)在[-1,1]上连续且满足f(x)=3x-√(1-x^2)∫(0,1)f^2(t)dt,求f(x)
人气:103 ℃ 时间:2019-12-04 05:28:17
解答
因为f(x)在[-1,1]上连续,则∫(0,1)f^2(t)dt存在,令A=∫(0,1)f^2(t)dt,于是f(x)=3x-A√(1-X^2)=>f^2(x)=9x^2-6Ax√(1-x^2)+A^2(1-X^2)又 A=∫(0,1)f^2(t)dt=∫(0,1)f^2(x)dx=∫(0,1)[9-A^2)x^2-6Ax√(1-x^2)+...
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