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求下列函数最小正周期,递增区间及最大值 (1)y=sin2xcos2x (2)y=2cosx/2
求下列函数最小正周期,递增区间及最大值
(1)y=sin2xcos2x
(2)y=2cosx/2+1
(3)y=√3cos4x+sin4x
人气:113 ℃ 时间:2019-11-22 14:55:15
解答
y = 2 sin2x cos2xy = sin4xT = 2π/4 = π/2ymin = -1 at 4x = 2kπ - π/2ymax = 1 at 4x = 2kπ + π/2递增区间[kπ/2 - π/8,kπ/2 + π/8],k∈Z------------------------------------------------------------y...第一题前面没有2的,化简后是1/2sin4x请问能把第一题再写一遍吗?我会采纳的好吧,我会了
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