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求下列函数的最小正周期 递增区间和最大值 (1) y=sin2xcos2x (2)y= 2cos
求下列函数的最小正周期 递增区间和最大值
(1) y=sin2xcos2x
(2)y= 2cos^x/2+1
(3)y=根号三cos4x+sin4x
人气:272 ℃ 时间:2019-08-22 13:00:50
解答
y = 2 sin2x cos2xy = sin4xT = 2π/4 = π/2ymin = -1 at 4x = 2kπ - π/2ymax = 1 at 4x = 2kπ + π/2递增区间[kπ/2 - π/8,kπ/2 + π/8],k∈Z------------------------------------------------------------y...谢谢你!
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