简单点是
到定点的距离比到定直线距离=√3/3√[(x-1)^2+y^2]/|3-x|=√3/3得到x^2/3+y^2/2=1详细√[(x-1)^2+y^2]/|3-x|=√3/3两边平方x^2-2x+1+y^2=1/3*(x^2-6x+9)3x^2-6x+3+3y^2=x^2-6x+92x^2+3y^2=6x^2/3+y^2/2=1请点击“采纳为满意答案”,祝学习进步！