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因式分解:6x^2-5xy+6y^2-xz-23yz-20z^2
人气:348 ℃ 时间:2020-07-03 23:02:48
解答
6x²-5xy-6y²-2xz-23yz-20z²
=6x^2-(5y+2z)x-6y^2-23yz-20z^2
=6[x^2-(5/6y+1/3z)x+(3/2y+2z)(-2/3y-5/3)z
=6(x-3/2y+2z)(x+2/3y+5/3z)
=(2x-3y+4z)(3x+2y+5z)
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