如何用错位相减法算求数列1乘2,3乘2^2,5乘2^3,...,(2n-1)乘2^n的前n项和Sn
人气:457 ℃ 时间:2019-10-23 09:33:23
解答
Sn=1*2+3*2^2+.(2n-1)*2^n2Sn=1*2^2+3*2^3+.(2n-2)*2^n+(2n-1)*2^(n+1)Sn-2Sn=2+2^3+2^4+.2^(n+1)-(2n-1)*2^(n+1)-Sn=2+2^3(1-2^(n-1))/(1-2)—(2n-1)*2^(n+1)Sn=n2^(n+2)+6—2^(n+1)* 是乘,^是乘方...
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