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(x的四次方-4x²+1)(x的四次方+3x²+1)+10x的四次方(因式分解,
人气:416 ℃ 时间:2019-08-18 00:42:52
解答
原式=x^8-x^6-10x^4-x^2+1+10x^4
=x^8-x^6-x^2+1
=x^6(x^2-1)-(x^2-1)
=(x^6-1)(x^2-1)
=(x^3+1)(x^3-1)(x+1)(x-1)
=(x+1)^2(x-1)^2(x^2+x+1)(x^2-x+1)这是正确答案吗你确定吗是的,我确定
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