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①4x²-y²+4x+1 ②(x+2)(x+4)+1 ③x的四次方-3x²-4
人气:499 ℃ 时间:2019-08-16 23:23:12
解答
:①4x²-y²+4x+1
=4x²+4x+1-y²
=(2x+1)^2-y^2
=(2x+1+y)(2x+1-y)
②(x+2)(x+4)+1
=x^2+6x+8+1
=x^2+6x+9
=(x+3)^2
③x的四次方-3x²-4
=(x^2-4)(x^2+1)
=(x+2)(x-2)(x^2+1)麻烦了,再问道,计算(2x+3y)²(2x-3y)²(2x+3y)²(2x-3y)²=[(2x+3y)(2x-3y)]^2=(4x^2-9y^2)^2=16x^4-72x^2y^2+81y^4
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