一样的题目,参考一下：已知抛物线y^2=6x,过点P(4,1)引一弦,使它恰在点P被平分,求这条弦所在的直线方程.设过点P(4,1)的直线方程为y-1=k(x-4)即y=k(x-4)+1 代入y^2=6xk^2x^2+2k(1-4k)x+(1-4k)^2=6xk^2x^2+2k(1-4k)x+(1...