1.sin(a+180°)cos(-a )sin(-a-180°) 2.sin三次方(-a)cos(2π+a)tan(-a-π)
人气:481 ℃ 时间:2020-04-03 20:04:46
解答
sin(a+180°)=-sina
cos(-a)=cosa
sin(-a-180°)=-sin(a+180°)=sina
sin(a+180°)cos(-a )sin(-a-180°)
=-sina cosa sina
=-(sina)²cosa
2)
sin^3(-a)cos(2π+a)tan(-a-π)
=-sin^3 a cosa (-tana)
=sin^3a cosa sina/cosa
=sin^4 a
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