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(y-1)(y+2)=2y(1-y)(因式分解)
人气:235 ℃ 时间:2020-09-10 22:13:23
解答
(y-1)(y+2)=2y(1-y)
(y-1)(y+2)-2y(1-y)=0
(y-1)(y+2)+2y(y-1)=0
(y-1)(y+2+2y)=0
(y-1)(3y+2)=0
所以y-1=0 y=1
或者3y+2=0 y=﹣2/3
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