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计算1/x(x+1)+1/(x+1)(x+2)+……+1/(x+8)(x+9)
人气:306 ℃ 时间:2020-04-21 03:47:07
解答
1/x(x+1)+1/(x+1)(x+2)+...+1/(x+8)(x+9)
=(1/x - 1/x+1) + (1/x+1 - 1/x+2) + ...+ (1/x+8 - 1/x+9)
=1/x - 1/x+9
=9/x(x+9)
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