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xy'-ylny=0 求可分离变量微分方程的通解
人气:360 ℃ 时间:2020-02-04 01:40:39
解答
xy'-ylny=0
∫ylny dy = ∫xdx
(1/2)∫lny dy^2 = (1/2)x^2
y^2lny -∫ ydy = x^2
y^2lny - (1/2) y^2 = x^2 + C
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