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因式分解ab(a+b)^2-(a+b)^2+1
人气:280 ℃ 时间:2020-03-26 11:22:01
解答
AB(A+B)^2-(A+B)^2 +1
=(AB-1)(A+B)^2+1
=(AB-1)A^2+(AB-1)B^2+2AB(AB-1)+1
=(AB-1)A^2+(AB-1)B^2+2(AB)^2-2AB+1
=(AB-1)A^2+(AB-1)B^2+(AB)^2+(AB)^2-2AB+1
=(AB-1)A^2+(AB-1)B^2+(AB)^2+(AB^2-2AB+1)
=(AB-1)A^2+(AB-1)B^2+(AB)^2+(AB-1)^2
=[(AB-1)A^2+(AB)^2]+[(AB-1)B^2+(AB-1)^2]
=A^2[(AB-1)+B^2]+(AB-1)*[(AB-1)+B^2]
=[A^2+(AB-1)]*[B^2+(AB-1)]
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