解
x²-y²+x³-y³
=(x-y)(x+y)+(x-y)(x²+xy+y²)
=(x-y)(x+y+x²+xy+y²)
x³-y³
=(x-y)(x²+xy+y)立方差公式лл,�һ���һ���ⷽ�̲����� ���Խ̽����� x4-7x2+6=0��x^4-7x²+6=0��a=x²��0��a²-7a+6=0��(a-6)(a-1)=0��a=6��a=1��x²=6��x²=1��x=��6��x=-��6��x=1��x=-1