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已知0<β<π/4,π/4<α<3π/4,cos(π/4-α)=3/5,sin(3π/4+β)=5/13,求sin(α+β
人气:393 ℃ 时间:2020-06-02 07:31:01
解答
因为π/4<α+β<π,所以sin(α+β)>0,
因为
-π/2<π/4-α<0,
cos(π/4-α)=3/5,
所以sin(π/4-α)= -4/5;
因为
3π/4<β+3π/4<π
sin(3π/4+β)=5/13
所以cos(3π/4+β)= -12/13
sin(3π/4+β-(π/4 -α))=sin(α+β+π/2)= - cos(α+β)=(5/13)*(3/5)-(-12/13)*(-4/5)=-33/65
sin(α+β)=√(1-(33/65)∧2)=(√3116)/65
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