设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大_数学解答

设lim（(x^2+1)/(x+1) -ax-b）=0,求a,b.x趋向无穷大

人气：409 ℃　时间：2019-12-10 11:06:45

解答

lim[(x^2+1)/(x+1) -ax-b]
=lim[(x+1)-2x/(x+1)-ax-b]
=lim[(1-a)x-(1+b)]
=0
1-a=0 a=1
1+b=0 b=-1