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若2x^2-6xy+9y^2-4x+4=0,则y/x-x/y=
若2x^2-6xy+9y^2-4x+4=0,则y/x-x/y=?
人气:330 ℃ 时间:2020-02-05 07:57:52
解答
2x^2-6xy+9y^2-4x+4=0
x^2-6xy+9y^2+x^2-4x+4=0
(x-3y)^2+(x-2)^2=0
x-3y=0
x-2=0
x=2,y=2/3
则y/x-x/y=1/3-3=-8/3
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