先求齐次的,再用待定系数求通解.
y’+2xy=0
dy/y=-2xdx
y=C1e^(-x^2)
设C1=u(x)
y'=u'(x)e^(-x^2)-2xu(x)e^(-x^2)代入原式得
u'(x)=x
u(x)=x^2/2+C2
y=(x^2/2+c)e^(-x^2)