k |
x |
k |
x |
(2)连接AC,则AC过E,过E做EG⊥BC交BC于G点
∵点E的横坐标为m,E在双曲线y=
3 |
x |

∴E的纵坐标是y=
3 |
m |
∵E为BD中点,
∴由平行四边形性质得出E为AC中点,
∴BG=GC=
1 |
2 |
∴AB=2EG=
6 |
m |
即A点的纵坐标是
6 |
m |
代入双曲线y=
3 |
x |
1 |
2 |
∴OB=
1 |
2 |
即BG=GC=m-
1 |
2 |
1 |
2 |
∴CO=
1 |
2 |
3 |
2 |
∴点C(
3 |
2 |
(3)当∠ABD=45°时,AB=AD,则有
6 |
m |
解之m1=
6 |
6 |
∴m=
6 |
k |
x |
k |
x |
k |
x |
k |
x |
3 |
x |
3 |
m |
1 |
2 |
6 |
m |
6 |
m |
3 |
x |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
3 |
2 |
3 |
2 |
6 |
m |
6 |
6 |
6 |