当xy≠0时,试说明代数式[（x+y)(x-y)-(x+y)²-2y(x-y)-2xy]/xy的值与x,y的值无关.我现_数学解答

当xy≠0时,试说明代数式[（x+y)(x-y)-(x+y)²-2y(x-y)-2xy]/xy的值与x,y的值无关.我现在就要

人气：292 ℃　时间：2019-08-18 18:19:33

解答

[（x+y)(x-y)-(x+y)²-2y(x-y)-2xy]/xy
=[x²-y²-x²-2xy-y²-2xy+2y²-2xy]/xy
=-6xy/xy
=-6