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2道简单的因式分解写下过程
(x-3)(x-1)(x+2)(x+4)+24
(x^2-5x)(x^2-5x-2)-24
人气:310 ℃ 时间:2020-05-14 06:25:58
解答
(x-3)(x-1)(x+2)(x+4)+24
=[(x-1)(x+2)]*[(x-3)(x+4)]+24
=(x^2+x-2)(x^2+x-12)-24
=(x^2+x)^2-14(x^2+x)-48
=(x^2+x-6)(x^2+x-8)
=(x-2)(x+3)(x^2+x-8)
(x^2-5x)(x^2-5x-2)-24
=(x^2-5x)^2-2(x^2-5x)-24
=(x^2-5x-6)(x^2-5x+4)
=(x-6)(x+1)(x-1)(x-4)
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