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当m为何值时,x2-y2-2x+8y+m能分解成2个一次因式的积
人气:231 ℃ 时间:2020-06-23 16:22:52
解答
x2-y2-2x+8y+m=(x²-2x+1)-(y²-8y+16)+m-1+16所以m-1+16=0m=-15 x2-y2-2x+8y-15=(x²-2x+1)-(y²-8y+16)=(x-1)²-(y-4)²=(x-1+y-4)(x-1-y+4)=(x+y-5)(x-y+3)
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