在斜三角形ABC中,tanA+tanB+tanC-tanAtanBtanC的值
人气：104 ℃ 时间：2019-10-09 10:28:05
解答
tanA+tanB=tan(A+B)(1-tanAtanB)所以原式=tan(A+B)(1-tanAtanB)+tanC-tanAtanBtanC=tan(A+B)+tanC-tan(A+B)tanAtanB-tanAtanBtanC=0因为tan(A+B)+tanC=tan(A+B+C)(1-tan(A+B)tanC)=0...
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