已知α第二象限的角,f(a)=sin(a+π/2)cos(3π/2-a)tan(2π-a)除以tan(-a-3π)sin(-a-2π)化简f(a)
人气:329 ℃ 时间:2020-05-25 16:01:19
解答
f(a)=sin(a+π/2)cos(3π/2-a)tan(2π-a)÷{tan(-a-3π)sin(-a-2π)}=cosa(-sina)(-tana)÷{[-tan(a+3π)][-sin(a+2π)]}=cosasinatana÷{[-tan(a+π)][-sina]}=cosasinatana÷{tan(a+π)sina}=cosasinatana÷{tana...
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