sinα=-12/13,cosα=√(1-sinα^2)=5/13
tanα=sinα/cosα=-12/5

2sin(π+α)+cos(2π-α)/cos(α-(π/2))-sin((3π/2)+α)=2(-sinα)+cosα/sinα+cosα=2x12/13-5/12+5/13=283/156谢谢