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证明左右相等的三角函数题
(secX + tanX)^2 = (1+sinX) / (1-sinX)
.怎么证明它们相等?
化简 ( X^2 - Y^2 )^2 + 4XY ( X + Y )^2
人气:407 ℃ 时间:2020-06-18 12:39:21
解答
(secX + tanX)^2 = (1+sinX) / (1-sinX) (sec^2 x + 2secx*tan x+ tan^2 x)=(1+sin x)(1+sin x)/(1-sin x)(1+sin x)(sec^2 x + 2*1/cos x * sin x/cos x + tan^2 x)=(1+sin x)^2/(1-sin^2 x)(sec^2 x + 2 sin x/cos^...
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