X^2-x*√（2x^2-3)=2-x
x+1-2/x =√（2x^2-3)
(x+1-2/x )^2=（2x^2-3)
(x^2-2)(x^2-2x+2)=0
x=±√2
2x^2-3≥0 x^2≥3/2 x=±√2满足
故：方程[X^2-x*根号（2x^2-3)=2-x]的实数解是x=±√2