求数列1/2,1/6,1/12,1/20,1/30,1/42的前n项和Sn
人气:434 ℃ 时间:2019-11-07 15:23:56
解答
sn=1/2+1/6+1/12+.+1/nx(n+1)=
=1/1x2+1/2x3+1/3x4+.+1/nx(n+1)=
=1-1/2+1/2-1/3+1/3-1/4+.+1/n-1/(n+1)=
=1-1/(n+1)=n/(n+1)(⊙o⊙)…懂了,谢谢了
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