先化简,再求值(1/2)x-2[2-(1/3)y]+[-(3/2)x+(1/3)y²]；其中x、y满足(x+2)²+丨y-2/3丨=0因为x、y满足(x+2)²+丨y-2/3丨=0,所以x=-1,y=2/3.故(1/2)x-2[2-(1/3)y]+[-(3/2)x+(1/3)y²]=[(1/2)-(3/2)]x...