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若|2x+y-3|与(y-2)²互为相反数,求4x²y-3xy的值?
人气:456 ℃ 时间:2020-01-28 14:16:18
解答
答:
|2x+y-3|与(y-2)²互为相反数,则有:
|2x+y-3|+(y-2)²=0
所以:
2x+y-3=0
y-2=0
解得:y=2,x=1/2
所以:
4x²y-3xy
=xy(4x-3)
=4x-3
=2-3
=-1
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