设A=2x²-3XY+Y²,B=4X²-6XY-3Y²,且(X-5)和(Y+2)²是互为相反数,求3A-2B的值
人气:369 ℃ 时间:2019-11-21 16:13:04
解答
(X-5)和(Y+2)²是互为相反数
则|x-5|+(Y+2)²0
则x-5=0,Y+2=0
则x=5,Y=-2
3A-2B
=3(2x²-3XY+Y²)-2(4X²-6XY-3Y²)
=6x²-9XY+3Y²-8x²+12XY+6Y²
=-2x²+3XY+9Y³
=-2×25+3×(-10)+9×4
=-50-30+36
=-44
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