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数学
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已知实数满足/2008-X/+根号x-2009=X,求x-2008²;的值
人气:208 ℃ 时间:2019-10-03 10:05:42
解答
|2008-X|+√(x-2009)=X,
x>=2009,
∴方程化为x-2008+√(x-2009)=x,
√(x-2009)=2008,
平方得x-2009=2008^2,
∴x-2008^2=2009.
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