过点O作OE⊥AB∵矩形ABCD∴BC⊥AB∵AB＝2,BC＝2√3∴AC＝√（AB²+BC²）＝√（4+12）＝4∵OE⊥AB∴OE∥BC∴OE/AO＝BC/AC∵AO＝m∴OE/ m＝2√3/4∴OE＝√3 m/2∵圆O的半径为1∴当OE＞1时,圆与AB相离当OE＝1...