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y=sin²xcos2x的导数是?
人气:473 ℃ 时间:2020-02-03 14:50:51
解答
∵y=(sinx)^2cos2x,
∴y′
=[(sinx)^2]′cos2x+(sinx)^2(cos2x)′
=2sinxcosxcos2x-2sin2x(sinx)^2.
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