>
数学
>
已知25a
2
-10a+1+|4b+1|=0,求[(4a+3b)(4a-3b)-(2a-5b)(8a+5b)]÷(-2b).
人气:143 ℃ 时间:2019-11-01 23:48:47
解答
∵25a
2
-10a+1+|4b+1|=0,∴(5a-1)
2
+|4b+1|=0,
∴a=
1
5
、b=
−
1
4
∴[(4a+3b)(4a-3b)-(2a-5b)(8a+5b)]÷(-2b)
=(16a
2
-9b
2
-16a
2
+25b
2
+30ab)÷(-2b)
=(16b
2
+30ab)÷(-2b)
=-8b-15a
=-8×(-
1
4
)-15×
1
5
=2-3
=-1.
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