1）(2x+2)/x-(x+2)/(x-2)=(x²-2)/(x²-2x)两边同时乘以x(x-2):(2x+2)(x-2)-x(x+2)=x²-22x²-4x+2x-4-x²-2x=x²-2-4x=2x=-1/2经检验此为原方程的解.2）由|x-2|+(2x-y-3)²=0得x-2=0且...