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3a^2-{5a(4a-1)-7a^2}
人气:390 ℃ 时间:2020-01-28 22:50:56
解答
3a^2-{5a(4a-1)-7a^2}
=3a^2-(20a^2-5a-7a^2)
=3a^2-(13a^2-5a)
=-10a^2+5a3a^2-{5a-(4a-1)-7a^2}3a^2-{5a-(4a-1)-7a^2}=3a^2-(5a-4a+1-7a^2)=3a^2-(a+1-7a^2)=3a^2-a-1+7a^2=10a^2-a-1
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