log2(2x)=log2(x)+1log4(16x²)=log4(16)+log4(x²)=2+log2(x)令log2(x)=t,则原方程化为：(t+1)(t+2)=6即：t²+3t-4=0(t+4)(t-1)=0t1=-4,t2=1即：log2(x)=-4或log2(x)=1得：x1=1/16,x2=2祝你...