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lim(x→0)(cosx-cos^2x)/x^2
人气:196 ℃ 时间:2020-04-02 04:31:32
解答
cosx(1-cosx)=cosx ×2sin²(x/2)
(cosx-cos²x)/x²= cosx ×2sin²(x/2)/x²
lim(x→0)cosx ×2sin²(x/2)/x²
= lim(x→0)cosx ×sin²(x/2)/2(x/2)²
∵ lim(x→0) sin(x/2)/(x/2)=1
lim(x→0)cosx =1
上面的式子=1/2
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