y'=2sin(1/x)*(sin1/x)'=2sin1/x*cos1/x*(1/x)'=sin2/x*(-1/x^2)=(-sin2/x)/x^2求y=e^_(sin1/x)^2的导数y=e^(sin1/x)^2设u=(sin1/x)^2,u'=-(sin2/x)/x^2y'=(e^u)'=e^u*u'=e^(sin1/x)^2*(-(sin2/x))/x^2谢谢不过有错阿哪里错了,请指正.