分解因式 1;x的4次方+x的平方+1 2;x的3次方+6x的平方+11x+6 3; a的平方+2b的平方+3c的平方+4ac+5bc+3ab
求详解
人气:496 ℃ 时间:2020-04-19 13:42:33
解答
x^4+x^2+1=(x^4+2x^2+1)- x^2=(x^2+1)^2-x^2=(x^2+x+1)(x^2-x+1)x^3-6x^2+11x+6=x^3-6x^2+9x+2x+6=x(x^2-6x+9)+2(x+3)=x(x-3)^2+2(x+3)=(x+3)(x^2+3x+2)=(x+3)(x+2)(x+1)a^2+2b^2+3c^2+4ac+5bc+3ab=(a^2+3ab+2b^2)+4...
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