已知函数Y=X四次方-4X²-3(-4≤X≤2),求函数的最大值与最小值.
人气:256 ℃ 时间:2019-10-19 19:18:05
解答
答:
y=x^4-4x^2-3,-4<=x<=2
设a=x^2,0<=a<=16
y=a^2-4a-3
抛物线y开口向上,对称轴a=2
a=2时取得最小值y=-7
a=16时取得最大值y=16^2-4*16-3=189
所以:
最大值189,最小值-7
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