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limx→∞,[x^(7/3)sin(pi/x^2)]/x^(1/3)
人气:187 ℃ 时间:2020-04-05 02:31:01
解答
limx→∞,[x^(7/3)sin(pi/x^2)]/x^(1/3)
=limx→∞ sin(pi/x^2)]/(1/x^(2))
=limx→∞ pisin(pi/x^2)]/(pi/x^(2))
=pi
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