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函数y=sinx(π /2
人气:191 ℃ 时间:2020-04-28 21:36:00
解答
∫ [π/2,5π/2] (1-sinx)dx
=(x+cosx)| [π/2,5π/2]
=5π/2 + cos(5π/2) - π/2 - cos(π/2)
=2π
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