证明：∵△ABC为等腰直角三角形∴AB=AC ∠ABC=45 °∵△ACD为等边三角形∴AD=AC ∠ADC=∠DAC=60 °∵AE⊥CD∴∠AED=90 °∠DAE=30 °∴AE=1/2AD 即DE=1/2AC又 ∵ ∠BAC=90 °∠DAC=60°AD=AB∴∠ADB=15°∴∠ODE=45...